Question

the system of equations :
e-y+2=4 ; x-2y-22.9 ; 2x+y +32.1​

Answer 1

Step-by-step explanation:

Given 2x−y+2z=2,x−2y+z=−4 and x+y+λz=4 then the value of λ such that the given system of equations has no solution is

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ANSWER

Given that the system of equation has no solution. Given equations are

2x−y+2z=2,x−2y+z=−4,x+y+λz=4

It will have no solution when A=0

A=

∣

∣

∣

∣

∣

∣

∣

∣

2

1

1

−1

−2

1

2

1

λ

∣

∣

∣

∣

∣

∣

∣

∣

=0

Apply c

2

→c

1

+2c

2

and c

3

→c

1

−c

3

So A=

∣

∣

∣

∣

∣

∣

∣

∣

2

1

1

0

−3

3

0

0

1−λ

∣

∣

∣

∣

∣

∣

∣

∣

=0

Solve it to get 1−λ=0⇒λ=