The system of linear equations 4x+2y=7 and 2x+y=6 has
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A1/a2=b1/b2=c1/c2: many solutions. A1/a2=b1/b2not equals to c1/c2:unique solutions. A1/a2not equals to b1/b2 not equals to c1/c2:no solution
Krish707:
4/2=2/1 not equals to 7/6: unique solutions
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Answer:
it has a unique solution
Step-by-step explanation:
given the equations 4x + 2y = 7
and 2x + y = 6
if a1/a2 = b1/b2 = c1/c2 , then the system of equations have infinitely many solutions. the two equations will be parallel lines.
if a1/a2 = b1/b2 ≠ c1/c2, then the graph intersect at one point and have a unique solution
if a1/a2 ≠ b1/b2, then there is no solution .
here a1/a2 = b1/b2 ≠ c1/c2
that is 4/2 = 2/1 ≠7/6
therefore it has a unique solution.
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