A ball weighs 80g in air, 60g in water and 50g in a liquid. If the density of water is 1gcm-3 , find the density of this liquid.
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Answered by
49
When the ball is immersed in water, it displaces some amount of water which is
(80 - 60) = 20g
Volume of water = 1 g cm^-3
Volume of ball = Volume of water it displaces
= 20g/ 1 = 20 cm^3
Density of ball = Mass/Volume
= 80/20 = 4 g cm^-3
But the ball displaces 80-50 = 30g of liquid
So density of liquid = 30/20 = 1.5 g cm^-3
Hence, density of liquid = 1.5 g cm^-3
(80 - 60) = 20g
Volume of water = 1 g cm^-3
Volume of ball = Volume of water it displaces
= 20g/ 1 = 20 cm^3
Density of ball = Mass/Volume
= 80/20 = 4 g cm^-3
But the ball displaces 80-50 = 30g of liquid
So density of liquid = 30/20 = 1.5 g cm^-3
Hence, density of liquid = 1.5 g cm^-3
divyanshroutnayak:
ya it helps
Answered by
9
When the ball is immersed in water, it displaces some amount of water which is
(80 - 60) = 20g
Volume of water = 1 g cm^-3
Volume of ball = Volume of water it displaces
= 20g/ 1 = 20 cm^3
Density of ball = Mass/Volume
= 80/20 = 4 g cm^-3
But the ball displaces 80-50 = 30g of liquid
So density of liquid = 30/20 = 1.5 g cm^-3
Hence, density of liquid = 1.5 g cm^-3
HOPE IT HELPS. .....
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