Question

the system shown in figure is given an acceleration 'a' toward left. Assuming all the surfaces to be inctionless
find the force on the sphere by inclined surface

Answer 1

Answer:

(3) 1.15 mg

Explanation:

1) Let the Normal Reaction by Inclined surface to be 'N1'.

Now, Let us draw Free Body Diagram of Sphere.

2) Since, there is no motion along vertical direction.

$=>N_1sin(60^{\circ})=mg\\ \\=>N_1=\frac{mg}{sin(60^{\circ})}=\frac{2mg}{\sqrt{3}}\\ \\ =>N_1 \approx 1.15 mg$

Note: Force on the sphere by the inclined surface is independent of 'a'.

Finally, Force on the sphere by the inclined surface is given by 1.15 mg.

Answer 2

Answer:

Explanation:

Note: Force on the sphere by the inclined surface is independent of 'a'.

Finally, Force on the sphere by the inclined surface is given by 1.15 mg.