Question

the system X+2y =3 and 5x+ky+7= 0 has no solution when​

Answer 1

Answer:

10

Step-by-step explanation:

Condition for no solution is,

a1/a2 = b1/b2 ≠ c1/c2

According to the question,

a1= 1, b1 = 2 and c1 = -3 in the first eqn.

In the second eqn, a2 = 5, b2 = k and c2 = 7

Substituting the values in the given condition,

1/5 = 2/k ≠ -3/7

⇒ 1/5 = 2/k

⇒ k = 10

Therefore, if the value of k is 10, then, the given pair of eqns have no solution.

Hope this helps you!!!

Answer 2

answer is k = 10

hope it helpful to you !