.The t1/2 of first order reaction is 60 minutes. What percentage will be left after 240 minutes?
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Answered by
0
Explanation:
k=
t
2.303
log
A
t
A
o
t=
0.693/60
2.303
log
A
t
A
o
240=
0.693/60
2.303
log
A
t
A
o
2.303×60
240×0.639
=log
A
t
A
o
log
A
t
A
o
=1.2036
Suppose A
o
=100
A
t
=6.25%.
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