The table below frequency table showing heights in inches of a sample of fe male clinic patients. Complete the empty cells in the table and calculate the sample variance by using the formula for grouped data.
Calculate Mean, Media Quartiles D3 D8 P20 P60 P75 Mode Geometric mean and Harmonuc mean and Box-and-whisker plots for the following data Also calculate these meatures wing MS Excel.
Answers
Solution :-
Class --------- Fi ------------ Xi ---- FiXi ------- CF
45 - 50 ------- 2 ---------- 47.5 ----- 95------- 2
50 - 55 --------3 ---------- 52.5 -----157.5----- 5
55 - 60 --------74 ----------57.5 --- 4255---- 79
60 - 65 --------212 ---------62.5 ----13250----291
65 - 70 ---------91 ----------67.5 ----6142.5----382
70 - 75 ---------18 ----------72.5 -----1305-----400
----------⅀ Fi = 400 ----------⅀FiXi = 25205
so,
→ Mean = ⅀FiXi / ⅀Fi = 25205/400 ≈ 63 (Ans.)
now,
→ n = 400 .
So,
→ (n/2) = 200 .
Then, Cumulative frequency greater than 200 is 291,
corresponds to the class 60 - 65.
Therefore,
→ Class 60 - 65 is the median class.
Now,
- Median = l + [{(n/2) - cf} / f] * h
from data we have :-
- l = lower limit of median class = 60
- n = total frequency = 400
- cf = Cumulative frequency of class before median class = 79 .
- f = frequency of median class = 212 .
- h = size of class = 5 .
Putting all value we get :-
→ Median = 60 + [(400 - 79)/212] * 5
→ Median = 60 + (321/212) * 10
→ Median = 60 + 15.14
→ Median = 75.14 (Ans.)
Learn more :-
Calculate mean median mode marks 0 10 20 30 40 50 60 70 80 no of student 150 140 100 80 80 70 80 14 0
https://brainly.in/question/2506805
Step-by-step explanation:
1. She isn't working on this problem yet.
2. I have never slept outside.
3. I am not sleeping well for months
Class --------- Fi ------------ Xi ---- FiXi ------- CF
45 - 50 ------- 2 ---------- 47.5 ----- 95------- 2
50 - 55 --------3 ---------- 52.5 -----157.5----- 5
55 - 60 --------74 ----------57.5 --- 4255---- 79
60 - 65 --------212 ---------62.5 ----13250----291
65 - 70 ---------91 ----------67.5 ----6142.5----382
70 - 75 ---------18 ----------72.5 -----1305-----400
----------⅀ Fi = 400 ----------⅀FiXi = 25205
so,
→ Mean = ⅀FiXi / ⅀Fi = 25205/400 ≈ 63 (Ans.)
now,
→ n = 400 .
So,
→ (n/2) = 200 .
Then, Cumulative frequency greater than 200 is 291,
corresponds to the class 60 - 65.
Therefore,
→ Class 60 - 65 is the median class.
Now,
Median = l + [{(n/2) - cf} / f] * h
from data we have :-
l = lower limit of median class = 60
n = total frequency = 400
cf = Cumulative frequency of class before median class = 79 .
f = frequency of median class = 212 .
h = size of class = 5 .
Putting all value we get :-
→ Median = 60 + [(400 - 79)/212] * 5
→ Median = 60 + (321/212) * 10
→ Median = 60 + 15.14
→ Median = 75.14 (Ans.)
Learn more :-
Calculate mean median mode marks 0 10 20 30 40 50 60 70 80 no of student 150 140 100 80 80 70 80 14 0
https://brainly.in/question/2506805