The table below shows the salaries of 280 persons:salary 5-10,10-15,15-20,20-25,25-30, 30-35,35-40,40-45,45-50 no.of people:49,133,63,15,6,15,6,7,4,2,1 find the median salary of the data
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Answers
Answered by
12
SOLUTION IS IN THE ATTACHMENT.
Median:
Median is that value of the given observation which divides it into exactly two parts.
MEDIAN for the GROUPED data :
For this we find the Cumulative frequency(cf) of all the classes and n/2 , where n = number of observations.
Now find the class whose Cumulative frequency is greater than and nearest to n/2 and this class is called median class,then use the following formula calculating the median.
MEDIAN = l + [(n/2 - cf )/f ] ×h
Where,
l = lower limit of the median class
n = number of observations
cf = cumulative frequency of class interval preceding the median class
f = frequency of median class
h = class size
HOPE THIS WILL HELP YOU..
Median:
Median is that value of the given observation which divides it into exactly two parts.
MEDIAN for the GROUPED data :
For this we find the Cumulative frequency(cf) of all the classes and n/2 , where n = number of observations.
Now find the class whose Cumulative frequency is greater than and nearest to n/2 and this class is called median class,then use the following formula calculating the median.
MEDIAN = l + [(n/2 - cf )/f ] ×h
Where,
l = lower limit of the median class
n = number of observations
cf = cumulative frequency of class interval preceding the median class
f = frequency of median class
h = class size
HOPE THIS WILL HELP YOU..
Attachments:
Answered by
2
Answer:
Step-by-step explanation:
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This question is related to statistics and I hope this is a question of CBSE 2018 class 10
okay so I will solve this by class 10 method
So let's begin
Total frequency is given 280
Now From median formula
lower limit + number of frequency/2- commutative frequency divided by frequency × class size
let's take the median class is 25-30
so lower limit of the median class 25
N/2= 280/2 = 140
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