Question

The table shows the heights of 5 students in inches. What is the mean absolute deviation for these numbers?



59 71 68 75 67

Answer 1

Step-by-step explanation:

x 5+9+7+1+6+8+7+5+6+7 =Êx =61

x² 25+81+49+1+36+64+49+25+36+49 =Èx² =415

Sd = [Êx²/n - (Êx/n )²]½

= [ 415/10 - (6.1)²] ½

= 4.29

MD/ SD = 12/15

MD = 12 × 4.29 / 15

= 3.432

Answer 2

Answer:

The mean absolute deviation is 4

Step-by-step explanation:

The given data is 59, 71, 68, 75, 67

The mean of the data

$=\frac{59+71+68+75+67}{5}$

= 68

59 - 68 = -9

71 - 68 = 3

68 - 68 = 0

75 - 68 = 7

67 - 68 = -1

Neglect the negative sign

The mean absolute deviation is given by

$=\frac{9+3+0+7+1}{5}$

$=\frac{20}{5}$

= 4

Therefore the mean absolute deviation is 4