The tangent at a point C of a circle and diameter BA when extended intersect at P such that angle PCA=10° find angle CBA
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In the circle Angle PCA=10°
THE CHORD CA MAKES THE ANGLE PCA WITH THE TANGENT AT THE POINT C .
THEREFORE, ANGLE CBA = ANGLE PCA
ANGLE CBA= 10° ( ALTERNALE ANGLE
OF THE CHORD RULE)
THE CHORD CA MAKES THE ANGLE PCA WITH THE TANGENT AT THE POINT C .
THEREFORE, ANGLE CBA = ANGLE PCA
ANGLE CBA= 10° ( ALTERNALE ANGLE
OF THE CHORD RULE)
pls send the diagram
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