: The taxi charges in a city comprise of a fixed charge together with the charge
for the distance covered. For a journey of 10 km, the charge paid is Rs 75 and for a
journey of 15 km, the charge paid is Rs 110.
Form linear equations to represent this situation.
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Answer:
Let the fixed charges of taxi be Rs x and the running charges be Rs y km/hr.
According to the given condition, we have 0
x+10y=75 .(i)
x+15y=110 .(ii)
Subtracting equation (ii) from equation (i), we get
−5y=−35⇒y=7
Putting y=7 in equation (i), we get x=5
∴ Total charges from travelling a distance of 25km
=x+25y
=Rs.(5+25×7)=Rs.180.
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