The taxi charges in a city comprise of a fixed charge together with the charge
for the distance covered. For a journey of 10 km, the charge paid is Rs 75 and for a
journey of 15 km, the charge paid is Rs 110.
Form linear equations to represent this situation.
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→Question: The taxi charges in a city comprise of a fixed charge together with the charge for the distance covered. For a journey of 10 km the charge paid is Rs. 75 and for a journey of 15 km the charge paid is Rs. 110. Form linear equations to represent this situation.
↔Answer: x+10y=75 - i)
x+15y=110 -ii)
are the linear equations formed.
⇒Fixed charges of tax = x and the running charges = Rs y km/hr.
⇒We can also find x and y:
⇔-5y = -35
∴y = 7
x + 15y =110
x + 15(7) =110
x + 105 =110
x = 110 -105
∴x = 5
Answered by
24
x+10y=75 - i)
x+15y=110 -ii) is the answers
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