Question

The taxi charges in a city consist of a fixed charge together with the charge for the distance covered . For a distance of 10 km , the charge paid is Rs 105 and for a journey of 15 km the charge paid is Rs 155. What are the fixed charges and the charge per km ?​

Answer 1

✬ Fixed Charge = Rs 5 ✬

✬ Charge per km = Rs 10 ✬

Step-by-step explanation:

Given:

• Taxi charges consists of a fixed charge together with the charge for the distance covered.
• For distance of 10 km charge paid is Rs 105.
• For distance of 15 km charge paid is Rs 155.

To Find:

• Value of fixed charge and charge per km?

Solution: Let the fixed charge be Rs x and charge per km is Rs y.

In first condition

• Distance travelled = 10 km
• So charge = 10y

Equation will be x + 10y = 105

➮ x + 10y = 105

➮ x = 105 – 10y.......(i)

In second condition

• Distance travelled = 15 km
• So charge = 15y

Equation will be x + 15y = 155......(ii)

Now putting the value of x in eqⁿ (ii) equation (i)

$\implies{\rm }$ x + 15y = 155

$\implies{\rm }$ 105 – 10y + 15y = 155

$\implies{\rm }$ 5y = 155 – 105

$\implies{\rm }$ y = 50/5

$\implies{\rm }$ y = 10

Now put the value of y in equation (i)

➮ x = 105 – 10y

➮ x = 105 – 10 × 10

➮ x = 105 – 100

➮ x = 5

So value of

• Fixed charge is Rs x = Rs 5

• Charge per km is Rs y = Rs 10

Answer 2

To Find :

• We need to find the fixed charge and charge for per km.

Sᴏʟᴜᴛɪᴏɴ :

Let the fixed charge be x and charge for per km be y.

Now,

$\underline{ \large \pink{ \mathscr{\dag\:A \bf{ccourding} \: to \: \mathscr {Q} \bf{uestion} ....}}}$

The taxi charges in a city consist of a fixed charge together with the charge for the distance covered.

For a distance of 10 km , the charge paid is Rs 105.

›› x + 10y = 105 ......(1)

And

For a journey of 15 km the charge paid is Rs 155.

›› x + 15y = 155 .....(2)

From Equation (1)

›› x = 105 - 10y ....(3)

• substituting value of x in (2)

›› x + 15y = 155

›› (105 - 10y) + 15y = 155

›› 105 + 5y = 155

›› 5y = 155 - 105

›› 5y = 50

›› y = 50/5

›› y = 10

• Substituting value of y in (3)

›› x = 105 - 10y

›› x = 105 - 10 × 10

›› x = 105 - 100

›› x = 5

$\large\dag \large { \red{\underline{\bf{Hence }}}}$

• Fixed charge x = 5 Rupees
• Charge for per km y = 10 Rupees