Question

the taxi fare in a city for the first kilometre the fare is 8 rupees and for the subsequent distance it is 5 rupee per kilometre taking the distance covered as X kilometre and the total fare as Y rupees write a linear equation for this information and draw its graph ​

Answer 1

Answer:-

Given:-

• The fare is 8 rupees per km
• Subsequent distance it is 5 rupees per km

To find:-

• Linear equation
• Graph

Solution:-

x   0   1    2

y   3   8   1

Taxi fare for first kilometer = RS.8

Taxi fare for subsequent distance = RS.5

Total distance covered = x

Total fare = y

Since the fare for first kilometer = RS.8

According to problem

Fare for (x-1)Kilometer = 5(x-1)

So, the total fare y = 5(x-1)+8

⇒y = 5(x-1)+8

⇒y = 5x-5+8

⇒y = 5x+3

Hence, y = 5x+3 is the required linear equation

Now the equation is

y = 5x+3-------(1)

Now putting the value x = 0 in (1)

y = 5×0+3

y=0+3=3 so the solution is (0,3)

Putting the value x = 1 in (1)

y = 5×1+3

y = 5+3 = 8 so the solution is (1,8)

putting the value x = 2 in (1)

y = 5×2+3

y = 10+3=13 so the solution is (2,13)

Mate the graph is in attachment