Question

the taxi fare in a city is as follows for the 1st km the fare is rupees 8 for the subsequent distance it is rupees 5 per km . taking the distance covered as x km and total fare as rupees y write a linear equations for this information and draw its graph

Answer 1

Given,Total distance covered= x km=1+(x-1)km

Fare For first kilometre= ₹8

Fare for subsequent distance= ₹5 per km

 

Fare for next(x-1)km= 5(x-1)

 

A.T.Q

 

Total fare= y

8+5(x-1)=y

8+5x-5=y

5x-y+3=0

Which is the required linear equation.

 

It can also be written as y= 5x+3

When X = 0 ,then Y = 3,When x=1, then y= 5+3=8

When x= 2, then y= 10+3=13

Answer 2

Answer:

let me try to think about it