Question

the taxi fare in a city is as follows :for the fare is Rs 8 and for the subsequent distance it is Rs5 per km . taking the distance covered by x km and total fare as Rs y write a linear equation for this information and draw its graph​

Answer 1

distance=x km

fare=y

y=5(x - 1)+8

y=5x-5+8

y=5x+3

take any value of X or y it's your choice I am taking the value of x

the box is given in the image

1st X=2

y=5x+3

y=5(2)+3

y=10+3=13

X =1

y=5(1)+3

y=5+3=8

X =0

y=5(0)+3

y=0+3=3

MARK AS BRAINLIEST

Answer 2

Answer:

distance=x km

fare=y

y=5(x - 1)+8

y=5x-5+8

y=5x+3

take any value of X or y it's your choice I am taking the value of x

the box is given in the image

1st X=2

y=5x+3

y=5(2)+3

y=10+3=13

X =1

y=5(1)+3

y=5+3=8

X =0

y=5(0)+3

y=0+3=3

Step-by-step explanation: