Question

the taxi fare in a city is as follows: for the first kilometer,fare in Rs.8 and for the subsequent distance it is Rs.5 per km.taking the distance covered as x km and total fare as Rs.y,write a linear equation for this information and draw its graph.

Answer 1

Fare for first km = Rs 8

Subsequent fare = Rs 5 per km

Distance covered = x km

Fare = Rs y

y = 8 + (x - 1)5

y = 5x + 3

Therefore, linear equation is 
y = 5x + 3

Answer 2

⇒ Let the total fare be = y Rs

⇒ Distance covered be = x km

⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)

⇒ y = 8 + 5 (x - 1)

⇒ y = 8 + 5x - 5

⇒ y = 5x + 3

⇒ The coordinates of the following linear equation

1) x = 0, y = 3 (0,3)

2) x = 1, y = 8 (1,8)

3) x = 2, y = 13 (2,13)

4) x = 3, y = 18 (3,18)