Question

The taxi fare in a city is as follows: For the first kilometre, the fares is Rs 8 and for the subsequent distance it is Rs 5 per km. Taking the distance covered as x km and total fare as Rs y, write a linear equation for this information, and draw its graph

Answer 1

Step-by-step explanation:

good morning have a great day ahead

Answer 2

Taxi fare for first kilometer = Rs. 8

Taxi fare for subsequent distance = Rs. 5

• Total distance covered =x
• Total fare =y

Since the fare for first kilometer = Rs.8

According to problem,

Fare for (x – 1) kilometer = 5(x − 1)

So, the total fare y = 5(x−1) + 8

⇒y = 5(x − 1) + 8

⇒y = 5x – 5 + 8

⇒y = 5x + 3

Hence, y = 5x + 3

is the required linear equation.

Now the equation is

y = 5x + 3 . . . . . . . (1)

Now, putting the value x = 0 in (1)

y = 5 × 0 + 3

y = 0 + 3 = 3 . . . So the solution is (0,3)

$\:$

Putting the value x = 1 in (1)

y = 5 × 1 + 3

y = 5 + 3 = 8 . . .So the solution is (1,8)

Putting the value x=2 in (1)

y = 5 × 2 + 3

y = 10 + 3 = 13 . . .So the solution is (2,13)

$\:$

$\small \red{ \bigstar}$ Graph Attached