the taxi fare in a city is rupees 8 for the first kilometre and for the subsequent distance it is rupees 5 per km. write linear equation and draw graph
Answers
Given,Total distance covered= x
km=1+(x-1)km
Fare For first kilometre= ₹8
Fare for subsequent distance= ₹5 per km
Fare for next(x-1)km= 5(x-1)
A.T.Q
Total fare= y
8+5(x-1)=y
8+5x-5=y
5x-y+3=0
Which is the required linear equation.
It can also be written as y= 5x+3
When X = 0 ,then Y = 3,When x=1, then y=
5+3=8
When x= 2, then y= 10+3=13
[Table & graph are on the attachment]
Now plot the points A(0,3), B(1,8), C(
2,13) on the graph paper and join them to form a line BC, which represents the
required graph of linear equation.
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Hope this will help you.....
⇒ Let the total fare be = y Rs
⇒ Distance covered be = x km
⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)
⇒ y = 8 + 5 (x - 1)
⇒ y = 8 + 5x - 5
⇒ y = 5x + 3
⇒ The coordinates of the following linear equation
1) x = 0, y = 3 (0,3)
2) x = 1, y = 8 (1,8)
3) x = 2, y = 13 (2,13)
4) x = 3, y = 18 (3,18)