Question

The taxi fare in a city is such that rs 50 is the fixed amount and rs 16 per km is charged.Taking the distance covered as x km and total fare as Rs y represent the situation algebraically and graphically Al's the taxi fare is20km distance is covered

Answer 1

Answer:

Let distance be x km and the total fare be y rs

  y=50+16x

 

  y=50+16(20)

   

  y=50+320

 

  y=370rs

Step-by-step explanation: I hope  this will help uhh !

Answer 2

Let y = Total fare of the journey .

and let total distance covered by taxi is = x km,

it is given that, fair per km is = rs 16

so,

fare of x km = 16x

and it is also given that = rs 50 is fixed amount,

so,

our equation algebraically is =

y = 50 + 16x

or ,

y -16x = 50 ..

now, when 20km distance is covered

Total fare will be ,

y = 50 + 16x

y = 50 + 16*20

y = 50+320

y = 370rs (Ans)

Therefore the total fare for 20 km is Rs 370 .