The taxi fare in a Delhi is as follows: For the first kilometer, the fare is Rs16 and for the subsequent distance it is Rs 10/km. Taking the distance covered as x km and total fare as Rs y, A linear equation for this information will be
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Answer:
Step-by-step explanation:
Given,Total distance covered= x km=1+(x-1)km
Fare For first kilometre= ₹8
Fare for subsequent distance= ₹5 per km
Fare for next(x-1)km= 5(x-1)
A.T.Q
Total fare= y
8+5(x-1)=y
8+5x-5=y
5x-y+3=0
Which is the required linear equation.
It can also be written as y= 5x+3
When X = 0 ,then Y = 3,When x=1, then y= 5+3=8
When x= 2, then y= 10+3=13
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