The taxi fare in city is such that rs50 is the fixed ammount and rs16 per km is charged .taking distance x km and total fare as rs.y. write linear equation in xy.what is the the total fare for 20km
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Let distance be x km
and the total fare be y rs
y=50+16x
y=50+16(20)
y=50+320
y=370rs
and the total fare be y rs
y=50+16x
y=50+16(20)
y=50+320
y=370rs
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Answer:
solution
y= ₹370
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