The taxi fare in city is such that Rs50 is the fixed amount and Rs16 per km is charged .Taking distance x km and totaj fare as Rs.y . Write linear equation in x y .What is the total fare for 20km ?
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Let distance be x km
and the total fare be y rs
y=50+16x
y=50+16(20)
y=50+320
y=370rs
y=50+16x
y=50+16(20)
y=50+320
y=370rs
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0
Concept
An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant.
Given
fixed fare of taxi = ₹50
fixed amount charged per km = ₹16
Find
we need to calculate the total fare for 20 km.
Solution
let x represent the distance traveled.
and y represent the total fare.
we get the required linear equation as,
total fare = fixed taxi fare × charge per km × distance
y = 50 ₊ 16x
y = 50 ₊ 16(20)
y = 50 ₊ 320
y = 370
hence we get the total fare for travelling 20 km as ₹370
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