The taxi fare in s city is as follows:-For the first kilometre,the fare is Rs8 and for the subsequent distance it is Rs5 per km. Talking the distance covered as xkm and total fare as Rsy, write a linear equation for this information and draw its graph
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Answered by
2
for 1st kilometre = Rs 8
for subsequent distance = Rs 5
Distance = x km
Total fare = Rs y
According to question,
8 × 1 + 5(x - 1) = y
=> 8 + 5x - 5 = y
=> 3 + 5x = y
HOPE IT HELPS YOU...
for subsequent distance = Rs 5
Distance = x km
Total fare = Rs y
According to question,
8 × 1 + 5(x - 1) = y
=> 8 + 5x - 5 = y
=> 3 + 5x = y
HOPE IT HELPS YOU...
Answered by
0
⇒ Let the total fare be = y Rs
⇒ Distance covered be = x km
⇒ For first subsequent distance (x - 1) km fare = 5(x - 1)
⇒ y = 8 + 5 (x - 1)
⇒ y = 8 + 5x - 5
⇒ y = 5x + 3
⇒ The coordinates of the following linear equation
1) x = 0, y = 3 (0,3)
2) x = 1, y = 8 (1,8)
3) x = 2, y = 13 (2,13)
4) x = 3, y = 18 (3,18)
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