The temperature at which 10% aqueous solution of (W/V) of glucose will show the osmotic pressure of 16.4 atom is (R = 0.082 L atom K-1 mol-1)
(a) 360°C
(b) 180 K
(c) 300 K
(d) 360 K
Answers
Answered by
3
The correct answer is (d) 360 K.
Explanation:
- We know that the molecular mass of glucose is 180 x kg.
- While p is 16.4 so using the formula PV = W/M RT.
- Replacing this with the given values in the question we get 360 K.
- The unit of W/M needs to be used here for specifications.
- This pressure represents the flow of any solvent through a specific material.
Answered by
0
The temperature at which 10% aqueous solution of (W/V) of glucose will show the osmotic pressure of 16.4 atom is 360 kelvin .
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