Use Euclid's division lemma to show that every odd integer is of the form 2p + 1
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Let a be a positive odd integer
a=bq+r
b=6
a=6q+r, 0≤r<6. So,the possible values of r are 0,1,2,3,4,5
Set of positive odd integers are {1,3,5,7,9......}
put a=1,3,5,7,9......
a=bq+r
1=6(0)+1=6q+1 [r=1]
3=6(0)+3=6q+3 [r=3]
5=6(0)+5=6q+5 [r=5]
7=6(1)+1=6q+1 [r=1]
9=6(1)+3=6q+3 [r=3]
So,any positive integer is of the form 6q+1,6q+3,6q+5 where q is certain integer.
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