Question

The temperature at which ice will begin to separate from a mixture of 20 mass percent of glycol in water is

Answer 1

Answer:

i think 20 .if it is right then like it

Answer 2

Answer:

265.5 K

Explanation:

ΔT=K * (moles of solute)/(weight of solvent in kg)

ΔT = 1.86 * $\frac{20}{62}$ * $\frac{1000}{80}$=7.5  C = 265.5 K