Question

the temperature at which the average speed of oxygen equal to that of Hydrogen at 20k

Answer 1

Answer:

The temperature at which average speed of Oxygen is equal to that of Hydrogen at 20 K is 320 K

Explanation:

We know that root mean square velocity of gaseous particles

$\boldsymbol{v_{rms}=\sqrt{\frac{RT}{M}}}$

Temperature of Hydrogen = 20 K

Given the average velocity of Oxygen is same as that of Hydrogen

Therefore,

$(v_{rms})_O=(v_{rms})_H$

$\implies \sqrt{\frac{RT_O}{M_O}}=\sqrt{\frac{RT_H}{M_H}}$

$\implies \frac{T_O}{32}=\frac{20}{2}$

$\implies {T_O}=320$

Thus the temperature at which average speed of Oxygen is equal to that of Hydrogen at 20 K is 320 K

Answer 2

Explanation:

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