Question

The temperature at which the volume of a gas at 10°cis doubled at constant P and n is​

Answer 1

Explanation:

Using gas equation, we have

(P1*V1) /T1=(P2*V2) /T2 where P=Pressure, V=Volume and T=Absolute temperature of the gas.

Given, P1=P2=P(say) (Since pressure is constant)

V1=V(say), where V is the initial volume of the gas.

Therefore, V2=2V since final volume is double the initial volume.

T1=(27+273)K=300K

T2=?

Substituting the values obtained,in the gas equation, we have

P*V/300=P*2V/T2

Solving, we get T2=final temperature of the gas=600K or (600–273)degree C or 327 degrees C.