Question

The temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. What is the final volume of the gas?
a. 1.0 dm3
b. 2.0 dm3
c. 3.0 dm3
d. 4.0 dm3

Answer 1

Answer:

a.1.0 dm

Explanation:

Remember the ideal gas law, well we can apply it:

P1V1/T1 = P2V2/T2

This comes from PV=nRT. If we are using the same amount of gas, then n is the same for before and after changing the conditions. Also, R would be the same as it is a constant.

We can then simplify to the above equation. Now you fill in what you know. The original temperature is 1, volume is 2 dm^3, and pressure is 1 (we can really call it any value because we know it is increased by a factor of 4). So we have this:

(1)(2)/1= P2V2/T2

Now we can figure out what happens after the expansion....

P2= 4x(original=1) = 4

Temperature=2, it was doubled.

V2= what we are looking for

Fill in:

2=V(4)/2

2=V2

V=1

Final volume=1

hopes it helps you....