Question

The van't hoff factor for 0.1 m b a ( n o 3 ) 2 0.1mba(no3)2 solution is 2.74. The degree of dissociation is

Answer 1

Answer:

actually, van't Hoff's factor for any reaction ,

A_n---->nA \\ 1 - \alpha \: \: \: \: \: \: \: \: \: \: \: \: \: \: n \alpha

then, van't Hoff factor ( i ) = 1 + (n -1)α

where α is the degree of dissociation .

similarly,

Ba(NO_3)_2---->Ba^+ +2NO_3^- \\ 1 - \alpha \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \alpha \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2\alpha

now , van't Hoff' factor { i } = 1 - α + α + 2α

2.74 = 1 + 2α

1.74 = 2α

α = 0.87

Answer 2

Answer:

I can't understand the question .........................