Question

The temperature of 170g of water at 50°C is lowered to 5°C by adding certain amount of ice to it. Find the mass of ice added. Give : Specific heat capacity of water = 4200 J kg-1°C-1 and specific latent heat of ice = 336000 J kg-1

Answer 1

Answer:

Given mass of water = 170 g = 0.17 kg T1 = 50°C, T2 = 5°C, specific heat capacity of water = 4200 J kg –1°C–1 Sp. Latent heat of ice = 336000 J kg–1 Let mass of ice added be x then we have heat lost by water = Heat used by ice. ⇒ water at 50°C to 5°C = ice at °C to water at °C + water at 0°C to 5°C

Explanation:

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