Question

The temperature of a black body is increased from 200 K
to 400 K. How will the ratio of emission of energy change?​

Answer 1

Answer:

E1: E2 = 1: 16

Explanation:

So, 16 E1 = E2

On increasing temperature, the energy of emission increases by 16 times

Answer 2

Answer:

Stefan's law :

It state that the amount of energy E radiated per second per unit area of a perfect black body is directly proportional to the fourth power of its absolute temperature.

i.e. E = σ T⁴

Here temperature becomes double.

i.e. 200 K to 400 K  [ Twice of initial ]

= > E = 2⁴

= > 16 times .

Therefore , ratio of emission of energy change is 1 : 16.