Chemistry, asked by varsha7183, 5 days ago

The temperature of a certain mass of gas in a rigid container is doubled. If initial pressure of gas is 1atm. Find the percentage increasing in the pressure (assume that volume is constant).​

Answers

Answered by Arnav151
2

Answer:

The percentage change in the pressure of a given mass of a gas filled in a container at constant temperature=100%

Find the percentage change in its volume=?

According to Charles and Boyle's law

PV=constant

If pressure increases, the volume decreases

InitialpressureFinalpressure

100200

P?(P

1

)

∴Finalpressure=

100

200P

Ifinitialvolume=V

Finalvolume=V

1

PV=P

1

V

1

P×V=

100

200P

V

1

V

1

=

200

100V

V=

2

1

V

V

1

=

2

1

V

∴Percentagechange=

V

(V−V

1

)×100

=(

2

V−

2

1

V

)×100

=

V

1/2V

×100

=

2

1

×50%

=50% decreases

Answered by sanirudhasaha05
2

Answer:

100percent

Explanation:

if the volume is constant,

P is proportional to {P=pressure,t=temperature}

if the temperature is doubled,

then, the the pressure will be doubled

then the pressure will increase 100 percent

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