the temperature of a city during the day was 95 degree fahrenheit it dropped by 5 degree celsius in the evening right the temperature of the city in the evening in Celsius please give correct answer answer me fast
Answers
Answered by
3
As per given
Temp in day time is 95 F
It is decreased by 5°C
5°C = 41F
Because C/100=F-32/180
5/100=F-32/180
1/20=F-32/180
9=F-32
F=41
It is decreased by 41F
95-41=54
Night temperature is 54F
Using the same relation
C/5=54-32/9
9C/5=22
9C=110
C=12.22°
Evening temperature= 12.22°C
Temp in day time is 95 F
It is decreased by 5°C
5°C = 41F
Because C/100=F-32/180
5/100=F-32/180
1/20=F-32/180
9=F-32
F=41
It is decreased by 41F
95-41=54
Night temperature is 54F
Using the same relation
C/5=54-32/9
9C/5=22
9C=110
C=12.22°
Evening temperature= 12.22°C
Answered by
1
c=Celsius
f=Fahrenheit
c/5=f-32/9
c/5=95-32/9 (f=95)
c/5=63/9
c/5=7
c=7×5
c=35 degree Celsius
5 degree Celsius temperature dropped in evening
=35-5
=30 degree Celsius ans
f=Fahrenheit
c/5=f-32/9
c/5=95-32/9 (f=95)
c/5=63/9
c/5=7
c=7×5
c=35 degree Celsius
5 degree Celsius temperature dropped in evening
=35-5
=30 degree Celsius ans
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