Question

The temperature of a liquid increases from (303 -+ 0.2) K to (307 +_ 0.6) K . The error in rise in temperature is​

Answer 1

Answer:

We know that If x=a−b

x±Δx=(a±Δa)−(b±Δb)

⇒±Δx=±(Δa+Δb)

∴ (76.3±0.3)−(67.7±0.2)

=(8.6±0.5)

0

C

Explanation:

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