Math, asked by SeemaJadon, 3 months ago

The temperature of a place at 10.00 AM was 16oC. Temperature increased by 8oC in the first hour

then decreased by 4oC in the second hour. What was the temperature at 12:00 noon?​

Attachments:

Answers

Answered by rdxofpubg
2

Answer:

20°C

Step-by-step explanation:

as the temperature is 16°C at 10:00 am

after increasing in one hour by 8°C it would be

16°C + 8°C = 24°C

and in second hour it is decreased by 4°C

so it would be

24°C - 4°C = 20°C (ans)

please mark me as Brainliest.

Similar questions