Question

The temperature of an ideal gas is increased from 140 K to
560 K. If at 140 K the root-mean square velocity of the gas
molecules is V, at 560 K it becomes
(a) 5V (b) 2V (c) V2 (d) V14​

Answer 1

Explanation:

The root mean square velocity is directly proportional to the square root of temperature.

Thus when the temperature increases from 140 K to 560 K, the root mean square velocity increases from u to root 560÷140u

=2u.