The temperature of ordinary electry bulb is about 27727°c.Find the wave length at which radiates maximum energy?
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Black body radiation..
According to Wien's displacement law, we have that the spectral radiance of a black body is highest for the wavelength λ given by :
λ = b / T
T = Absolute temperature of the black body
b = Wien's displacement constant = 2, 897.77 micrometers-Kelvin
≈ 2900 μm-°K
Given T = 27, 727° C = 28000 °K
λ = 2897.77 /28000 micrometers
= 0.10349 μm
= 103.49 nm This will be in the range of Ultraviolet rays ...
According to Wien's displacement law, we have that the spectral radiance of a black body is highest for the wavelength λ given by :
λ = b / T
T = Absolute temperature of the black body
b = Wien's displacement constant = 2, 897.77 micrometers-Kelvin
≈ 2900 μm-°K
Given T = 27, 727° C = 28000 °K
λ = 2897.77 /28000 micrometers
= 0.10349 μm
= 103.49 nm This will be in the range of Ultraviolet rays ...
kvnmurty:
:-)
nice :)
Sir, Can we take approximation here ? Like is it ok for medical students to take approximation?
Significant use in case of approximation . Then I think this valid in all exams :)
Ok! Thanks Abhi :)
significant figure you know very well , if i am right
:)
yes approximate answer will be okay.
yes abhi I know significant figures
and thank you sir for help
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the wavelength is 103.49 lamda
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