Question

The temperature T1 and T2 of heat resrviors in the idol carnot engine are 1500 degree celcius and respectively if T1 increases by 100 degree celcius the efficiency of the engine is ​

Answer 1

Answer:

We can use, Efficiency = 1 – T2/T1 = (T1-T2) / T1. Increasing the temperature T1 by 100°C, E = (1600 – 500 ) / (1600 + 273) = 59%

Answer 2

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