Math, asked by renudhuliya107, 1 year ago

The ten digit of a two digit number exceeds the unit digit by 5 if the digits are reversed the new number is less by 45 if the sum of the digit is 9 find the numbers

Answers

Answered by legend04
1

Answer: the answer is 72


Answered by yajat1810
11
let the no. be 10x+y
x = y+5
10x+y = 45+10y+x
9(x-y) = 45
x-y = 5…………................….………(1)
x+y = 9…………..…..………………...(2)
add (1)&(2)
2x = 14
x = 7
y = 2
hence the no. is 72
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