The ten's digit of a two digit number exceed it's unit by 5 . When digits are reversed , the new number added to the original number becomes 99,. Find the original number .
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x+5 = y .......(i)
(10y + x )+ (10x + y) = 99
11x + 11y = 99
11( x + y ) = 99
x + y = 9.......(ii)
adding (i) and (ii)
(x + y) + (x - y) = 9 + 5
2x = 14
x = 7
putting this value of x in eq (i)
y = 7+5
= 12
the original number = 10x + y
= 70 + 12
= 82, ANSWER
(10y + x )+ (10x + y) = 99
11x + 11y = 99
11( x + y ) = 99
x + y = 9.......(ii)
adding (i) and (ii)
(x + y) + (x - y) = 9 + 5
2x = 14
x = 7
putting this value of x in eq (i)
y = 7+5
= 12
the original number = 10x + y
= 70 + 12
= 82, ANSWER
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