The ten's digit of a two digit number exceed it'sunit by 5 . When digits are reversed , the new number added to original number becomes 99 . Find the original number . plzz answer it plzzzzzz
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Let tens digit number=x
Let unit digit=x+5
Number=10x+(x+5)
a/q
10x+(x+5)+10(x+5)+x=99
10x+x+5+10x+50+x=99
22x+55=99
22x=99-55
22x=44
x=44/22
x=2
Number =10x+(x+5)
x=2
10×2+2+5
=27
Number=27
If any doubt ask
Let unit digit=x+5
Number=10x+(x+5)
a/q
10x+(x+5)+10(x+5)+x=99
10x+x+5+10x+50+x=99
22x+55=99
22x=99-55
22x=44
x=44/22
x=2
Number =10x+(x+5)
x=2
10×2+2+5
=27
Number=27
If any doubt ask
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