Question

The ten's digit of a two-digit number is twice the digit in unit's place. If the ten'
digit is made half and its units digit is doubled then the new number obtained
is less than the original number by 27. Find the number,
​

Answer 1

Step-by-step explanation:

Let the two digit no. be 10x+y in which x is tens digit and y is unit digit so,

According to the problem,

x=2y ......(1)

Again, when tens digit is being made half and unit digit is doubled then no. obtained is less than original no. by 27, Then eq. becomes,

(10 x+y)-(5x+2y)=27 .....(2)

putting the value of x in (2)from(1)

10×2y+y-5×2y-2y=27

20y+y-10y-2y=27

21y-12y=27

9y=27,y=3

now,x=2y

x=6

Hence the no.is 63 .

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Answer 2

Answer:

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