the ten' s digit of a two digit number is twice the unit's digit. The sum of the number and its unit's digit is 66. find the number.
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Let number be xy.
Number can be written as 10x + y.
x = 2y(given)
Sum if number and unit's digit is 66.
10x + y + y = 66
10x +2y = 66
Replace value of 2y with x as given.
10x +x = 66
11x = 66
x = 6
And 2y = x
2y = 6
y = 3
So the number is xy = 63.
Thank you.
Number can be written as 10x + y.
x = 2y(given)
Sum if number and unit's digit is 66.
10x + y + y = 66
10x +2y = 66
Replace value of 2y with x as given.
10x +x = 66
11x = 66
x = 6
And 2y = x
2y = 6
y = 3
So the number is xy = 63.
Thank you.
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