Question

the tens digit is four times its ones digit. if 27 is subtracted from the number, the digits of the difference obtained are reverse of those of the number. find the number.
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Answer 1

Answer:

Let us assume x is a tenth place digit and y is one's place digit.

Therefore, the number is 10x + y

Given:

x = 4y ------------1

Also given:

10x + y - 27 = 10y + x

9x - 9y = 27

x - y = 3 ------------2

Substitute the value of x from equation 1 in equation 2

4y - y = 3

3y = 3

y = 1

Therefore, x = 4y = 4 * 1 = 4

The number = 10 * 4 + 1 = 41

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