The tens digit of 2-digit number is less than the ones digit by 3 . If the digit are reversed ,the difference between the two numbers is 27 . If the sum of the digit is 11 , find the number.
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Step-by-step explanation:
Let X be the 1s digit of a number, X−3 is the 10s digit,
The number is 10(X−3)+X .
Reverse the number so X−3 is 1s digit and X is 10s digits,
Number becomes 10(X)+(X−3)
The SUM of digits is 11 hence
X+(X−3)=11
2X=14
X=7
10s digit=4 , 1s digit=7 , the number is 47.
The reverse is 74 , and 74−47=27 is true.
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Answer:
Number is 47 and Reverse is 74
Step-by-step explanation:
the guy who answered b4 me is correct
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