Question

the tens digit of a two digit number exceed the unit digits by 4.if the sum of the digits is 10. find the number

Answer 1

Let the two digit number be 10x + y

The tens digit exceed the unit digit by 4
Therefore
x - y = 4 (equation 1)

Sum of the digits = 10
x + y = 10 (equation 2)

Adding equation 1 and 2
x - y = 4
x + y = 10

2x = 14
x = 7

7 - y = 4
y = 3

The number is 10x + y = 10*7 + 3 = 73

Answer 2

let the number be 19x+y
given x+y=10----(1)
x-y=4------(2)
from 1&2,
2x=14
x=7
substitute value of x in (1)
7+y=10
y=3

therefore the number is 10×7+3
=73

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