Question

the tens digit of a two digit number exceeds the unit digit by 5 if the digits are reversed the new number is less by 45 if the sum of their digits is 9 find the numbers

Answer 1

Let the units digit be y,
and the tens digit be x.
Thus the number is 10x+y
according to the condition,
(10x+y)-(10y+x) =45
9(x - y)=45
x-y=5.......(1)
also x+y=9...(given)
Adding(1) and (2)

2x=14
x=7
Putting in (1)
y=7-5
y=2

Thus the number is 72.
Hope this helps.

Answer 2

Answer:

Step-by-step explanation:

Let the units digit be y,

and the tens digit be x.

The new number is less than 45

(10x+y-45=10y+x

9x-9y=45

x-y=5

also x+y=9...(given)

Adding(1) and (2)

2x=14

x=7

Putting in (1)

y=7-5

y=2

Thus the number is 72.

Hope this helps.