The tens digit of a two-digit number is 3 more than the digit at the units place. When the digits are reversed.
the new number added to the original number is 121. Find the original number.
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Answer:
let the ones digit be x and tens digit be y
number = yx
y = X +3...........1 equation
number with digits reversed = xy
xy + yx = 121
x(x+3)+(x+3)x = 121
now solve the equation
hope it will help you
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